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October 20, 2005 12:00 AM

The Logical Puzzle

SQL Server Pro
InstantDoc ID #48166
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SOLUTION TO NOVEMBER'S PUZZLE: CUTTING A STICK TO MAKE A TRIANGLE
In last month's puzzle, you cut a stick in two random places, then had to figure out the probability that you could form a triangle out of the three pieces.

In order for the three pieces to form a triangle, all pieces must be shorter than half the length of the original stick. In a triangle, the sum of the lengths of any two sides is always longer than the length of the remaining side. If a piece ends up being longer than half the stick's size, the sum of the other two pieces will be shorter and you will not be able to form a triangle.

To avoid having a piece that is at least half the length of the stick, the two cuts must be on opposite sides of the middle point. The probability of this occurring is ½ (either both cuts end up on the same half or not). Now assume that the first cut is made on point p (where p is a percentage of the full length of the stick). In addition, the second cut must fall below the p + ½ point.The probability for this is of course ½ . Now multiply the two probabilities and you get the final answer: ½ × ½ = ¼ .

DECEMBER'S PUZZLE: RECTANGLE WITHIN A CIRCLE
This month's logical puzzle is a geometrical one. Examine Figure A and see whether you can calculate the length of the circle's radius.

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Comments
  • Ulises
    7 years ago
    Dec 19, 2005

    5

  • preethi
    7 years ago
    Nov 22, 2005

    Also, I see an error on the solution of the November puzzle.
    Let me give an example. You have a stick of 5'. If you cut 1' from each end (both are shorter than half of the length and falls on oppersite side of themiddle point. However, you can't make a triangle because the largest piece is larger than half of the original length .
    To make a triangle, the sum of two smaller sticks' length should exceed the biggest stick's length.

  • preethi
    7 years ago
    Nov 22, 2005

    Radius is 5. quite obvious

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